1.92 Ft) (8e23p75)water in an irrigation ditch of width w m and depth d= 1.14 m
ID: 1656844 • Letter: 1
Question
1.92 Ft) (8e23p75)water in an irrigation ditch of width w m and depth d= 1.14 m flows with a speed of 0.107 m/s. The mass flux of the flowing water through an imaginary surface is the product of the water's density (1000 kg/m3) and its volume flux through that surface. Find the mass flux through the following imaginary surfaces: (a) a surface of area wd, entirely in the water, perpendicular to the flow; (in kg/s) 10. AO 5.63 × 101 DO 1.32 × 102 GO 3.11 × 102 BO 7.48 × 101 EO 1.76 × 102 HO 4.14 × 102 co 9.95 × 101 FO 234 × 102 c24p5) An infinite nonconducting sheet has a surfacrExplanation / Answer
Answer:
Given, width w = 1.92 m, depth d = 1.14 m; speedv = 0.107 m/s and density = 1000kg/m3.
Notethe irrigation ditch is rather a canal of water. Also note thatvolume flus or velocit flux is like elctric flux(v.a andE.A),where A is the area vector. Also,v, E and A arevector quantities, but flux is scalar.
Therefore the massflux of water is given by v.A and has SI units,kg/s.
)Mass flux of water over the area w.d, = v.A = v.w.d
= 1000x0.107x1.92x1.14 = 234.20kg/s.
=2.34*10^2kg/s
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