At an airport, luggage is negligible. The coupling bars have negligible mass fro
ID: 778540 • Letter: A
Question
At an airport, luggage is negligible. The coupling bars have negligible mass from a plane into the three cars of a luggage carrier, as the drawing shows. The of the carrier is 0.13 m /s2 and friction is Coupling Caping Capling (a) By how much would the tension in each of the coupling bars A, B, and C change if 22 kg of luggage were removed from car 3 and placed in car 1? If the tension changes, specify whether it increases or decreases. (Specify a decrease in tension with a negative value and an increase in tension with a positive value. If there is no change, enter O.) ATC- (b) By how much would the tension in each of the coupling bars A, B, and C change if 22 kig of luggage were removed from car changes, specify whether it increases or decreases. ( change, enter 0.) increase in tension with a positive value. If there is no Specify a decrease in tension with a negative value and an ATB- TC- Section 4.1 20FExplanation / Answer
let mass of the three cars are m1,m2 and m3 for car 1, car 2 and car 3.
using force mass relationship:
Tension in coupling bar A=Ta=(m1+m2+m3)*a
where a=acceleration=0.13 m/s^2
tension in coupling bar B=Tb=(m3+m2)*a
tension in coupling bar C=Tc=m3*a
new mass in car 3=m3-22
new mass in car 1=m1+22
then new tension in A=Ta1=(m1+22+m2+m3-22)*a=Ta
so change in Ta=0
new tension in B=(m2+m3-22)*a
change in tension=-22*a=-2.86 N
new tension in C=(m3-22)*a
change in tension =-22*a=-2.86 N
part b:
new mass in car 3=m3+22
new mass in car 1=m1-22
then new tension in A=Ta1=(m1+22+m2+m3-22)*a=Ta
so change in Ta=0
new tension in B=(m2+m3+22)*a
change in tension=22*a=2.86 N
new tension in C=(m3+22)*a
change in tension =22*a=2.86 N
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