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At an airport, luggage is negligible. The coupling bars have negligible mass fro

ID: 778540 • Letter: A

Question

At an airport, luggage is negligible. The coupling bars have negligible mass from a plane into the three cars of a luggage carrier, as the drawing shows. The of the carrier is 0.13 m /s2 and friction is Coupling Caping Capling (a) By how much would the tension in each of the coupling bars A, B, and C change if 22 kg of luggage were removed from car 3 and placed in car 1? If the tension changes, specify whether it increases or decreases. (Specify a decrease in tension with a negative value and an increase in tension with a positive value. If there is no change, enter O.) ATC- (b) By how much would the tension in each of the coupling bars A, B, and C change if 22 kig of luggage were removed from car changes, specify whether it increases or decreases. ( change, enter 0.) increase in tension with a positive value. If there is no Specify a decrease in tension with a negative value and an ATB- TC- Section 4.1 20F

Explanation / Answer

let mass of the three cars are m1,m2 and m3 for car 1, car 2 and car 3.

using force mass relationship:

Tension in coupling bar A=Ta=(m1+m2+m3)*a

where a=acceleration=0.13 m/s^2

tension in coupling bar B=Tb=(m3+m2)*a

tension in coupling bar C=Tc=m3*a

new mass in car 3=m3-22

new mass in car 1=m1+22

then new tension in A=Ta1=(m1+22+m2+m3-22)*a=Ta

so change in Ta=0

new tension in B=(m2+m3-22)*a

change in tension=-22*a=-2.86 N

new tension in C=(m3-22)*a

change in tension =-22*a=-2.86 N

part b:

new mass in car 3=m3+22

new mass in car 1=m1-22

then new tension in A=Ta1=(m1+22+m2+m3-22)*a=Ta

so change in Ta=0

new tension in B=(m2+m3+22)*a

change in tension=22*a=2.86 N

new tension in C=(m3+22)*a

change in tension =22*a=2.86 N

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