At a winter fair a 62.1-kg stunt man is shot from a horizontal cannon that rests

Question

At a winter fair a 62.1-kg stunt man is shot from a horizontal cannon that rests at the edge of a frozen lake. The human projectile is cast onto the smooth ice, slides some distance, and grabs the end of a long rope whose other end is attached to a pivot that is firmly anchored to the ice. The rope initially lies perpendicular to the stunt man's line of motion, and when he grabs it, he starts sliding in circular motion about the pivot and continues to revolve until he comes to rest. A tensometer on the rope indicates a tension of 831 N at the beginning of the circular motion. With a coefficient of kinetic friction of 0.0451, how many revolutions does the stunt man make? Take g = 9.81 m/s2. Assume the rope supplies all the centripetal force. Ive seen this question but i dont understand where some values are coming from because they arent explained. please explain where every number that doesnt appear in the problem comes from

Explanation / Answer

let h be the height of the frozen lake then the speed of the human on reaching the bottom is

v = sqrt(2gh)

if T is the tension in the ropoe then tension will be equal to centripetal force (m v2 / r)

831 N = (m v2 / r)

= (62.1 kg) (v2) / r

here we must be known with the radius of the circular path without radius we cant get the number of revolutions

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