3) In the resistor network below R, and R, are in series with the parallel equiv

Question

3) In the resistor network below R, and R, are in series with the parallel equivale resistance of the parallel resistors: R,R,. don't assume a number). Write a function that takes as input a row vector whose first two elements are the series resistors and from the 3rd element on, the parallel resistors. The function should call the function you wrote in class that computes both series and parallel resistances and returns them in a vector. You probably have to call it several times. Test your function with several sets of resistors and show the results of the tests. 345' etc...

Explanation / Answer

consider if R1=R2=R3=R4=R5=..... =Rn= R

hence R3,R4,R5,.... are arranged inparallel hence we know,

1/Rparallel = 1/( R3) + 1/( R4)+ 1/( R5)+ 1/( R6) + ......  +1/( Rn)

1/Rparallel = 1/( R) + 1/( R)+ 1/( R)+ 1/( R) + ......  +1/( R) =n/R

Rparallel =R/n

now this is in series with R1 and R2

hence

Req = R1+R2+Rparallel

Req = R+R+R/n = 2R+R/n = R(2n+1)/n

Req = R(2n+1)/n

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