3) Four charged particles (two having a charge +Q and two having a charge -Q) ar

Question

3) Four charged particles (two having a charge +Q and two having a charge -Q) are arranged in the lane, as shown in the figure. These particles are all equidistant from the origin. The electric potential (relative to infinity) at point P on the z-axis due to these particles, is A) negative. B) zero. C) positive. D) impossible to determine based on the information given. ifference Vo and gains a speed vo. If it were accelerated instead through a potential difference of 2Von what speed would it gain? C) 4vo A) von/2 B) 8vo 5) A hydrogen atom consists of a proton and an electron. If the orbital radius of the electron increases, the electric potential energy of the electron due to the proton B) increases. A) remains the same. D) depends on the zero point of the potential. C) decreases.

Explanation / Answer

3] Electric potential due to a charge Q at distance r = (1/4*pi*epsilon0)*Q/r

Also from superposition principle to get the potential due to a system of charges, we just need to add the potential due to each charge in the system.

There are two +Q charges and two -Q charges, all equidistant from the point P.

Hence, V= (1/4*pi*epsilon0)*Q/r+(1/4*pi*epsilon0)*Q/r-(1/4*pi*epsilon0)*Q/r-(1/4*pi*epsilon0)*Q/r=0

4] Kinetic energy of a proton accelerated from rest through a potential difference V0=eV0=0.5*m*v02

v0=sqrt(2*eV0/m)

Now in case of acceleration through 2V0,

v=sqrt(2*e*2V0/m)=sqrt(2)*v0

5]

Electric potential energy of electron due to proton=U=-(1/4*pi*epsilon0)*e2/r

where r= orbital radius of electron

Thus of r increases, U becomes less negative i.e. U increases

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