1. (35 pts) A tennis ball is hit with a speed of 24.1 m/s at an angle of s the t

Question

1. (35 pts) A tennis ball is hit with a speed of 24.1 m/s at an angle of s the tennis balil ohe ball in from a height of 0.550 m above the ground. The opposing pand downward part of its motion at a height of 1.23 m above the air just before it is hit by the opposing player? B) How horizontally in this time? C) What is the direction o player hits the tennis ball on the ts motion at a height of 1.23 m above the ground. tnis ball travel far does the travel. A) How long is the ball in t is the direction of the velocity just before the ball is hit by the the racket of the other player, does the ball or the racket experience the larger force? Explain Pictorial Representation

Explanation / Answer

7. in vertical,

yf - yi = v0y t + ay t^2 / 2

1.23 - 0.550 = (24.1 sin48.2)(t) - 9.8 t^2 /2

4.9 t^2 - 18t + 0.680 = 0

t = 3.63 sec ......Ans(A)

(B) x = (v0x) t

x = (24.1 cos48.2)(3.64)

x = 58.3 m

(C) vx = v0x = 24.1 cos48.2 = 16.1 m/s

vy = v0y - gt = (24.1 sin48.2) - (9.8 x 3.64)

vy = - 17.7 m/s

theta = tan^-1(17.7 / 16.1) = 47.7 deg below horizontal.

(D) they will experience force of same magnitdue.

(from Newton's 3rd law)

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