A bar is moved at a constant downward velocity across a \"u-shaped\" wire with a
ID: 776600 • Letter: A
Question
A bar is moved at a constant downward velocity across a "u-shaped" wire with a resistor in a magnetic field B that points out of the page (the +z-direction) as shown. 1) What is the direction of the magnetic force on a positive charge in the moving rod? -X +Z -Z the magnetic force is zero Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What direction does current flow through the resistor? from left to right from right to left there is no induced current in the resistorExplanation / Answer
1)
magnetic force Fb = q( V X B )
V = -vj
B = Bk
Fb = q*(-vj X Bk )
Fb = q*v*B (-j X k )
Fb = qvB (-i)
-x <<--------ANSWER
==========================
2)
as the rod moves down, the magnetic flux increases
the induced magnetic field is into the page
By right hand rule
the current is clockwise
the current flows from right to left
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3)
magnetic force Fb = I*( L X B)
Fb = I*( -Li X Bk )
Fb = I*L*B ( -i X K )
Fb = ILB j
+y <<<-----ANSWER
==========================
4)
Fb = -q*( vi X -Bk)
FB = qvB ( i X k )
Fb = qvB -j
-y
======================
5)
as theloop moves , the magnetic flux decreases
the induced magnetic field is into the page
By right hand rule
the current is clockwise
the current flows from leftt to right
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