1) A coin slides over a frictionless plane and across an xy coordinate system fr
ID: 776595 • Letter: 1
Question
1) A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (1.90 m, 7.70 m) while a constant force acts on it. The force has magnitude 4.80 N and is directed at a counterclockwise angle of 103.° from the positive direction of the x axis. How much work is done by the force on the coin during the displacement?
2) The figure here shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.90 N, F2 = 3.50 N, and F3 = 10.0 N, and the indicated angles are 2 = 52.0 and 3 = 32.0 . What is the net work done on the canister by the three forces during the first 3.60 m of displacement?
Explanation / Answer
1)
work = force*distance*cos (theta)
where theta is the angle between the force and the direction of motion
component of force in x direction = 4.8N cos 103 = -1.079N
component of force in y direction = 4.8 sin 103=4.676N
work = -1.079x1.9m + 4.676Nx7.7m
=33.962J
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