1) A coin rests 16.5 cm from the center of a turntable. The coefficient of stati

Question

1) A coin rests 16.5 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface is 0.400. The turntable starts from rest at t = 0 and rotates with a constant angular acceleration of 0.660 rad/s2.

(a) Once the turntable starts to rotate, what force causes the centripetal acceleration when the coin is stationary relative to the turntable? Under what condition does the coin begin to move relative to the turntable?

________________________________________________

(b) After what period of time will the coin start to slip on the turntable?

____________s

Explanation / Answer

part a )

static friction stop coin to move .

when force exceed the static friction

Fc > us*N

part b )

wf = wi + alpha*t

wf = 0 + 0.660*t

it will start slip

mw^2r > mu*m*g

w^2r > mu*g

(alpha*t)^2r > mu*g

t^2 = mu*g/(alpah^2 * r )

t =7.385 s

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