Draw the experimental outcome for a titration analysis involving a titrant and t

Question

Draw the experimental outcome for a titration analysis involving a titrant and titrand (the pH vs. volume titrant added response curve), wherein the titrand is the weak, monoprotic base aniline (0.05000 F, 0.10000 L), and the titrant is a strong monoprotic acid (0.1000 M) that has been standardized. Calculate what the pH is at 0 mL added strong acid, the quarter-, half-, and three-quarter-equivalence points, the equivalence point, and when excess acid has been added. For the last point, pick a volume roughly 5 mL past the equivalence volume and calculate the pH. What is the pH at 1 mL past the equivalence volume (you

Explanation / Answer

mono protic base means one OH- ion comes from that base..

mono protic acid means one H+ ion comes from that acid..

1)

when zero amount of acid is added

means it is completely base

POH =- log [OH-]

OH- CONC = 0.05/0.1 =0.5

POH= - log(0.5)

POH= 0.30

PH= 14- PoH = 14-0.301029 = 13.69

2)

when quater of acid is added = 0.1/4 =0.025 M

base = 0.5 M

after tiration = 0.5-0.025 = 0.475

POH = - log [0.475] =0.323

PH = 14-0.323 =13.67

3)

when half of acid is added = 0.1/2 =0.05 M

base = 0.5 M

after tiration = 0.5-0.05 = 0.45

POH = - log [0.45] =0.346

PH = 14-0.346 =13.65

4)

when three-quarteof acid is added =0.1 *0.75 = 0.075

base = 0.5 M

after tiration = 0.5-0.075= 0.425

POH = - log [0.425] =0.3716

PH = 14-0.346 =13.6283

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