Draw in a point of rotaion on the crane boom. You can choose any point but the b

Question

Draw in a point of rotaion on the crane boom. You can choose any point but the best one would be a place where you eliminate the torque from the unknown forces. (not the one you are trying to find).

Look at the forces acting on the boom and state whether each one will cause the boom to rotate clockwise, counterclockwise, or not at all. if the answer is not at all, then write why this is true.

Now suppose the mass of the boom is 2.7 kg, Theta = 34 degrees, and the length of the boom is 1.2 m. Writet he equation for the sum of the torques on the beam making the counterclockwise torques positive and the clockwise ones negative. Recall that since the boom is in equilibrium this sum must be equal to zero.   

Find the Tension in the rope. (Answer: 19.6 N)

Draw in a point of rotaion on the crane boom. You can choose any point but the best one would be a place where you eliminate the torque from the unknown forces. (not the one you are trying to find). Look at the forces acting on the boom and state whether each one will cause the boom to rotate clockwise, counterclockwise, or not at all. if the answer is not at all, then write why this is true. Now suppose the mass of the boom is 2.7 kg, Theta = 34 degrees, and the length of the boom is 1.2 m. Writet he equation for the sum of the torques on the beam making the counterclockwise torques positive and the clockwise ones negative. Recall that since the boom is in equilibrium this sum must be equal to zero. Find the Tension in the rope. (Answer: 19.6 N)

Explanation / Answer

Here , let the tension in the string is T

Let's balance the torque about O ,

T*l*sin(theta) - mg*l*cos(theta)/2 = 0

T*sin(34) - 2.7 * 9.8 * cos(34)/2 = 0

T = 19.6 N

the tension in the string is 19.6 N

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