tert-Butyl alcohol is a solvent with a of 9.10 celsius/mole and a freezing point

Question

tert-Butyl alcohol is a solvent with a of 9.10 celsius/mole and a freezing point of 25.5 celsius . When 0.807g of an unknown colorless liquid was dissolved in 11.6 of tert-butyl alcohol, the solution froze at 15.3 celsius. Which of the following is most likely the identity of this unknown liquid?

ethylene glycol (molar mass = 62.07) 1-octanol (molar mass = 130.22) glycerol (molar mass = 92.09) 2-pentanone (molar mass = 86.13) 1-butanol (molar mass = 74.12)

Explanation / Answer

delta T = 15.3 - 25.5 = - 10.2 10.2 = 9.10 x m m = 1.12 1.12 = moles solute / 0.0116 Kg moles solute = 0.0130 MM = 0.807 / 0.0130 = 62.1 g/mol => ethylene glycol Molar mass = 0.185 g x 0.08206 x 301 K / 0.138 x 0.00200 L = 16556 g/mol

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