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Two students prepare two cyclohexane solutions having the same freezing point. S

ID: 764516 • Letter: T

Question

Two students prepare two cyclohexane solutions having the same freezing point. Student 1 uses 26.6 g of cyclohexane solvent, and student 2 uses 24.1 g of cyclohexane solvent. Which student has the greater number of moles of solute? I tried the problem using the following equation ( I do not know if it is the right equation to be using however): moles solute = Delta Tf (change in freezing point) x mass (kg) of solvent / kf kf of cyclohexane= 20.0 I'm not sure what to do next since no change in freezing point was given. Any help would be much appreciated :) Note: I'm reposting this question because some of the explanations I have found so far did not make sense.

Explanation / Answer

molality of both the solutions remains the same. as student 1 uses more amount of solvent, the weight of solute should also be high. so student 1 has more no. of moles of solute.

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