1.- At 25 o C, the following heats of reaction areknown: 2ClF(g) + O 2 (g) ---->

Question

1.- At 25oC, the following heats of reaction areknown: 2ClF(g) + O2(g) ----> Cl2O(g)+ F2O              Horxn= 167.4 kJ/mol 2ClF3(g) + 2O2(g) ---->Cl2O(g) + 3F2O(g)   Horxn= 341.4 kJ/mol 2F2(g) + O2(g) ---->2F2O(g)                           Horxn= -43.4 kJ/mol At the same temperature, use Hess's law to calculateHorxn for the reaction: ClF(g) + F2(g) ----> ClF3(g) a) -217.5 kJ/mol    b) -130.2kJ/mol     c) 217.5kJ/mol     d) 465.4 kJ/mol   e)-108.7 kJ/mol 1.- At 25oC, the following heats of reaction areknown: 2ClF(g) + O2(g) ----> Cl2O(g)+ F2O              Horxn= 167.4 kJ/mol 2ClF3(g) + 2O2(g) ---->Cl2O(g) + 3F2O(g)   Horxn= 341.4 kJ/mol 2F2(g) + O2(g) ---->2F2O(g)                           Horxn= -43.4 kJ/mol At the same temperature, use Hess's law to calculateHorxn for the reaction: ClF(g) + F2(g) ----> ClF3(g) a) -217.5 kJ/mol    b) -130.2kJ/mol     c) 217.5kJ/mol     d) 465.4 kJ/mol   e)-108.7 kJ/mol

Explanation / Answer

2ClF(g) + O2(g) ----> Cl2O(g)+ F2O      ;        Ho1 = 167.4 kJ/mol   ------------------ eq ( 1 ) 2ClF3(g) + 2O2(g) ---->Cl2O(g) + 3F2O(g)  ; Ho2 = 341.4kJ/mol     ------------------ eq ( 2 ) 2F2(g) + O2(g) ---->2F2O(g)                     ;      Ho3 = -43.4 kJ/mol   ------------------ eq ( 3 ) The required equation   ClF(g) + F2(g)----> ClF3(g) ; H     canbe obtained by   bf the following sequencial order ( 1/ 2 ) Eq ( 1 ) + ( 1/2 ) reverse of Eq ( 2 ) + ( 1/ 2) Eq ( 3 ) H = ( 1/2)  Ho1 + ( 1/ 2 ) ( -Ho2 ) + ( 1/ 2)  Ho3       = ( 1/2 ) 167.4 + ( 1/ 2 )( - 341.4 ) + ( 1/ 2 )  ( -43.4 )       = -108.7 KJ / mol

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