The decomposition of a certain ether was studied at 300 K and the data was plott

Question

The decomposition of a certain ether was studied at 300 K and the data was plotted in a graph. The Y intercept equals 2.75 and the slope and the slope of the line is equal to -5. 0 X 10^ -3. Under these conditions, how long would it take for a sample to decompose to 25% of it original concentration?

Explanation / Answer

A=A' e^(-k*t) ln A = ln A' - k*t y = c + mx c = ln A' = 2.75 => A' = 15.642 m = - k = - 5 * 10^-3 => k = 5 * 10^-3 A=A' e^(-k*t) since, A = 25% A' therefore, A/A' = 0.25 therefore, 0.25 = e^(-k*t) => ln 0.25 = -k *t => -1.386 = - k * t => 1.386 = 5 * 10^-3 * t => t = 1386 / 5 seconds => t = 277.2 seconds

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