net ionic equation? Cr(OH)3 (s) + 3HNO2 (aq) ------> Cr(NO2)3 (aq) + 3H2O (l) So

Question

Explanation / Answer

note that (s) = solid, cannot be dissosiated into ions, insoluble RbOH(aq) + HNO3(aq) ----> RbNO3(aq) + H2O (l) NIE : Rb+ (aq) + OH-(aq) + H+ (aq) + NO3- (aq) -----> Rb+ (aq) + NO3- (aq) + H2O (l) after elliminate the same ions in products and reactants, we get: H+ (aq) + OH- (aq) ----> H2O (l) HCl(aq) + NaCH3COO (aq) -----> NaCl (aq) + CH3COOH (aq) NIE : H+ (aq) + Cl- (aq) + Na+ (aq) + CH3COO- (aq) -----> Na+ (aq) + Cl- (aq) + CH3COO- (aq) + H+ (aq) elliminate it, and the NIE is nothing 3FeSO4 (aq) + 2Na3PO4 (aq) ------> Fe3(PO4)2 (s) + 3Na2SO4 (aq) NIE: 3Fe2+ (aq) + 3SO42- (aq) + 6Na+ (aq) + 2PO43- (aq) -----> Fe3(PO4)2 (s) + 6Na+ (aq) + 3SO42- (aq) elliminated, we get 3Fe2+ (aq) + 2PO43- (aq) ----> Fe3(PO4)2 (s) Mn(ClO4)2 (aq) + 2NaOH (aq) -------> Mn(OH)2 (s) + 2NaClO4 (aq) Ca(OH)2 (aq) + (NH4)2CO3 (aq) -------> CaCO3 (s) + 2NH4OH (aq) FeI2 (aq) + 2NaS (aq) ----> FeS2 (s) + 2NaI (aq) HgCl2 (s) + 2HF (aq) -----> HgF2 (s) + 2HCl (aq) (NH4)2SO4 (aq) + 2AgNO3 (aq) ----> Ag2SO4 (s) + 2NH4NO3 (aq) ZnS (s) + 2HBr (aq) -----> ZnBr2 (aq) + H2S (aq) Cr(OH)3 (s) + 3HNO2 (aq) ------> Cr(NO2)3 (aq) + 3H2O (l) that's all. hope it helps =D

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.