The solubility product constant (Ksp) for the dissolution of PbSO4 as represente

Question

The solubility product constant (Ksp) for the dissolution of PbSO4 as represented by the chemical equation is 1.7x10-8. PbSO4 (s) Pb2+ (aq) + SO42- (aq) Calculate the molar solubility (mol/L) of PbSO4 in water. Molar Mass (g/mol) PbSO4 303.26

Explanation / Answer

The solubility product constant (Ksp) for the dissolution of PbSO4 as represented by the chemical equation is 1.7x10-8 Molar Mass of PbSO4 = 303.26g/mol PbSO4 (s) ----> Pb2+ (aq) + SO42- (aq) Calculate the mass (g) of PbSO4 that dissolves in 900 mL of water Let x = mol/L of PbSO4 that dissolve : this will give x mol/L Pb2è and x mol/L SO42- Ksp = 1.7 x 10^-8 = [Pb2+][SO42-]= (x)(x) x = molar solubility = 0.00013 M Mass PbSO4 = 0.00013 mol/L x 0.900 L x 303.26 g/mol= 0.036 g

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