Balance the following oxidation-reduction reaction using the half-reaction metho

Question

Balance the following oxidation-reduction reaction using the half-reaction method. Cr2O7(2-) + I2 --> Cr(3+) + IO3- In the balanced equation, the coefficient of water is: a) 4 b) 17 c) 11 d) 7 e) 6

Explanation / Answer

Cr2O7(charge on O7 is 2-) + H(charge is 1+) + I2 --------> Cr (charge is 3-) + IO3(charge on O3 is 1-) + H2O (Acidic) Cr2O7^2- + H+ + I2 --> Cr^3+ + IO3^- + H2O 5(14H+ + Cr2O7^2- + 6e- --> 2Cr^3+ + 7H2O ) 3(I2 + 6H2O --> 2IO3^- + 12H+ + 10e-) --------------------------------------… 70H+ + 5Cr2O7^2- + 3I2 + 18H2O --> 10Cr^3+ + 6IO3^- + 35H2O + 36H+ simplify H+ and H2O 34H+ + 5Cr2O7^2- + 3I2 --> 10Cr^3+ + 6IO3^- + 17H2O

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