Balance the following equation in basic solution. Fe(CN) 6 3- (aq) + Re(s) Fe(CN

Question

Balance the following equation in basic solution.

Fe(CN)63-(aq) + Re(s) Fe(CN)64-(aq) + ReO4-(aq)

What is the coefficient of water?

2

3

4

1

6

You might need to use Appendix C from your book to answer this question.

The reaction below is spontaneous under standard conditions - true or false?

Cl2(g) + Fe2+(aq) Fe3+(aq) + Cl-(aq)

True

False

a.

2

b.

3

c.

4

d.

1

e.

6

You might need to use Appendix C from your book to answer this question.

The reaction below is spontaneous under standard conditions - true or false?

Cl2(g) + Fe2+(aq) Fe3+(aq) + Cl-(aq)

1.

True

2.

False

Explanation / Answer

Answer (1)

The balanced equation in acidic solution is
7 Fe(CN)6 3- + Re + 4 H2O = 7 Fe(CN)6 4- + ReO4- + 8 H+

add 8 OH- on the left and on the right
( remember that 8 OH- + 8 H+ = 8 H2O)

7 Fe(CN)6 3- + Re + 4 H2O + 8 OH- = 7 Fe(CN)6 4- + ReO4- +8 H2O

Balanced eqaution :
7 Fe(CN)6 3- + Re + 8 OH- = 7 Fe(CN)6 4- + ReO4- + 4 H2O

So the Answer is (c) 4

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