Sodium bicarbonate reacts with citric acid as shown below: What is the theoretic

Question

Sodium bicarbonate reacts with citric acid as shown below: What is the theoretical yield of sodium citrate (Na3C6H5O7) when 3.1 g of sodium bicarbonate reacts with 4.4 g of citric acid?

Explanation / Answer

3NaHCO3 + C6H8O7 -----> Na3C6H5O7 + 3CO2 + 3H2O moles of sodium bicarbonate = 3.1 / 84 = 0.0369 moles of citric acid = 4.4 / 192 =0.0229166 since one mole citric acid requires 3 moles sodium bicarbonate thererfore 0.0229166 moles citric acid requires 0.0687498 moles of sodium bicarbonate since there is not that much sodium bicarbonate so it acts as limitting reagent since 3 moles sodium bicarbonate gives one mole of sodium citrate so 0.0369 moles gives 0.0123 moles of sodium citrate so mass of sodium citrate produced = 0.0123 * 258 = 3.1734 g ans.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.