onsider the reaction N2 (g) + O2 (g) ? 2 NO (g).a. How many g NO can be produced

Question

onsider the reaction N2 (g) + O2 (g) ? 2 NO (g).a. How many g NO can be produced when 25.0 g of nitrogen reacts?b. How many g NO can be produced when 25.0 g of oxygen reacts?c. Based on your answers in a and b, predict the amount of NO that can be produced when 25.0 g nitrogen is reacted with 25.0 g of oxygen.d. Explain the reasoning used in

Explanation / Answer

first off, starts with balancing equation: N2 (g) + O2 (g) --> 2 NO (g) A) *every 1 mole of N2 contains 28.0 gram of N2 ---(25.0g N2)(1 mol N2)/(28.0g N2) = 0.893 mol N2 *2 moles of NO is produced from 1 mole of N2 ---(0.893 mol N2)(2 mol NO/1 mol N2) = 1.79 mol NO *every 1 mole of NO has 30.0 gram (14.0 + 16.0) ---(1.79 mol NO)(30.0 g NO/1 mol NO) = 53.7 g NO So, Part A, 53.7 g of NO was produced from 25.0 grams of N2 (assuming excess amount of oxygen) B) same as above except its oxygen ---(25.0g O2)(1 mol O2)/(32.0g O2) = 0.781 mol O2 ---(0.781 mol O2)(2 mol NO/1 mol O2) = 1.56 mol NO ---(1.56 mol NO)(30.0 g NO/1 mol NO) = 46.8 g NO So, Part B, 46.8 g of NO was produced from 25.0 grams of O2 (assuming excess amount of nitrogen) C) The total amount of NO can be produced from 25.0 g of N2 and O2 will be 46.8 g D) 46.8 g of NO is produced from this reaction is because oxygen was the limiting reactants. Another reason is that oxygen has higher molar mass than nitrogen (oxygen = 32.0g, nitrogen = 28.0 g) and after converting from mass to moles, you end up with smaller amount of moles of oxygen than nitrogen.

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