A plot of 1/[A] versus time for the hypothetical reaction givenbelow yields a st

Question

A plot of 1/[A] versus time for the hypothetical reaction givenbelow yields a straight line. A B + C If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction? A B + C If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction? If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction?

Explanation / Answer

For first order reactions, the graph of 1/[A] Vstime would be a straight line Formula : ln[A]t = -kt +ln[A]0                ln(0.61*35%) = -k*49s + ln0.61                ln(0.61*35/100) = -k*49s + ln0.61                ln0.2135 = -k*49s + ln0.61                        - 1.544 = -k*49s - 0.49                          k = 0.0215s-1 Hence the rate constant is0.0215s-1 Hence the rate constant is0.0215s-1

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.