For the reaction 2H2 + O2 ---> 2H2O how much water is produced when 2.5 moles of

Question

For the reaction 2H2 + O2 ---> 2H2O how much water is produced when 2.5 moles of hydrogen react completely? A) 2.5 grams B) 18.0 grams C) 2.0 moles D) 2.5 moles 2. When we see the equation CH4(g) + 2O2(g) ---> 2H2O(g) + CO2(g), we understand it to mean which of the following? A) we cannot carry out the reaction if we do not have exactly 1 mole of CH4(g) and 2 moles of O2(g) B) if we have a certain weight of CH4(g) we need twice that weight of O2(g) C) if we have 16.0 grams of CH4(g) we need 64.0 grams of O2(g) to completely react with the CH4(g) D) none of the above 3. What is the weight of the KCl residue when 3.00 grams of KClO3(s) is decomposed according to the reaction 2KClO3(s) ---> 2KCl(s) + 3O2(g)? A) 0.193. g B) 1.37 g C) 1.83 g D) 2.74 g 4. Ammonia can be produced industrially by the Haber process. The chemical reaction is 3H2(g) + N2(g) ----> 2NH3(g) What weight of hydrogen is needed to produce 51.0 grams of ammonia? A) 3.00 g B) 4.50 g C) 6.00 g D) 9.00 g 5. If a sample of sodium is dropped into a container of water the reaction is 2Na(s) + 2H2O(l) ---> 2NaOH(aq) + H2(g) What weight of hydrogen is produced when 2.3 grams of sodium is dropped into 100 mL of water? A) 0.10 g B) 0.20g C) 0.23 g D) 0.40 g

Explanation / Answer

2H2 + O2 => 2H2O First you want to convert it to moles H2O. So you multiply 2 moles H2 (as seen by the first number of 2H2 in the balanced equation) times 2 mole H2O/1 mole H2. This will cancel out your moles H2 and leave you with moles H2O. So: 2 mol H2*(2 mol H2O/1 mol H2) = 4 mol H2O Then multiply that by the atomic mass of H2O, which is 18 grams per mole. 2 hydrogen weigh 2 grams per mole, and 1 oxygen weighs 16 grams per mole. Therefore: 4 mol H2O*(18 grams/1 mole H2O)= 72 grams per mole H2O

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