Ammonia reacts with chlorine gas to produce nitrogen gas and hydrogen chloride g

Question

Ammonia reacts with chlorine gas to produce nitrogen gas and hydrogen chloride gas. How many liters of hydrogen chloride gas at 2.40 atm and 250K can be produced from 6.5 Liters of ammonia gas at 1.50 atm and 265K provided excess chlorine gas is available?

Explanation / Answer

2 NH3 + 3 Cl2 ----> N2 + 6 HCl Now 2 moles of ammonia gives 6 moles of HCl now we have PV = nRT => mole n = PV/RT => mole of NH3 = 1.5 * 6.5/ 0.0821 * 265 = 0.448 now mole of HCl formed = 6/2 * 0.448 = 1.344 hence volume of HCl = nRT/P = 1.344 * 0.0821 * 250/2.4 = 11.494 L

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