How many milliliters of 0.100 M NaOH solution are required to neutralize a solut

Question

How many milliliters of 0.100 M NaOH solution are required to neutralize a solution containing 3.92 g H2SO4?

400 mL

800. mL

200. mL

0.400 mL

0.800 mL

Explanation / Answer

You always need an equation and to convert to moles in this sort of question. So the equation: 2NaOH + H2SO4 -> 2H2O + Na2SO4 This tells us the ratio of NaOH : H2SO4 is 2:1 Convert H2SO4 to mole: 3.92 g of H2SO4 = 3.92 / 98.079 = 0.0399 mol This means that only half this amount of NaOH is required to react because of the 2:1 ratio. So n(NaOH) = 0.0799 mol. Since the concentration is 0.1 M, we can use c = n/v rearranged to v = n/c. v = 0.0799 / 0.1 = 0.800 L = 800 mL.

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