12. Based on the solubility rules, which of these processes will occur when a so

Question

12. Based on the solubility rules, which of these processes will occur when a solution containing about 0.1 g of Pb(NO3)2(aq) is mixed with a solution containing 0.1 g of KI(aq)/100 mL?

A. KNO3 will precipitate; Pb2+ and I- are spectator ions.
B. No precipitate will form.
C. Pb(NO3)2 will precipitate; K+ and I- are spectator ions.
D. PbI2 will precipitate; K+ and NO3- are spectator ions.
E. Pb2+ and I- are spectator ions, and PbI2 will precipitate.

Explanation / Answer

Ksp of PbI2 = 7.1 x 10^-9 moles lead nitrate = 0.1 / 331.2 g/mol=0.00030 moles KI = 0.1 / 166 g/mol=0.00060 [Pb2+]= 0.00030/ 0.100 L = 0.0030 [I-]= 0.00060 / 0.100 L = 0.0060 Qsp = 0.0030(0.0060)^2 =1.1 x 10^-7 >> Ksp PbI2 will precipitate and K+ and NO3- are spectator ions

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