The equilibrium constant for the reaction 1/3 NH3(g)----> 1/6 N2(g) + 1/2 H2(g)

Question

The equilibrium constant for the reaction

1/3 NH3(g)----> 1/6 N2(g) + 1/2 H2(g)


is Keq = 1.98e-01 at 331 K. Calculate Keq for the reaction 1/6 N2(g) + 1/2 H2(g) ---> 1/3 NH3(g) at this temperature and figure out whether the equilibrium favors N2 and H2 or NH3 at this temperature. Pick the correct choice from below.



a) Keq = 1.31e+00; At this temperature the reaction favors NH3.
b) Keq = 1.67e+04; At this temperature the reaction favors N2 and H2.
c) Keq = 5.06e+00; At this temperature the reaction favors NH3.
d) Keq = 6.03e-05; At this temperature the reaction favors NH3.
e) Keq = 7.63e-01; At this temperature the reaction favors N2 and H2.

Explanation / Answer

c) Keq = 5.06e+00; At this temperature the reaction favors NH3.

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