Two moles of a gas (closed system) that obeys the equation of state P = (nRT/V)

Question

Two moles of a gas (closed system) that obeys the equation of state P = (nRT/V) - (n2a/V2) undergo a reversible, isothermal expansion from an initial volume of Vi to a final volume of 10 V1 and thereby do -9,000 J of work. The temperature is 261.3 K and a = 6.17 L2 bar mol-2 for this gas. Calculate the initial volume V1 and the final pressure p2 for this change of state. 8.56 L, 0.504 bar 27.3 L, 0.159 bar 27.3 L, 1.92 bar 2.21 L, 0.504 bar 0.117 L, 19.1 bar 8.56 L, 0.159 bar 85.6 L, 0.0507 bar 85.6 L, 19.1 bar 0.117 L, 0.0507 bar 2.21 L, 1.92 bar

Explanation / Answer

option g

p=nrt/v -n2a/v2

vf=10v1

so

putting value

.504=n

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