The reaction 2 NO(g) + Cl2(g) --> 2 NOCl(g) proceeds through the following mecha

Question

The reaction 2 NO(g) + Cl2(g) --> 2 NOCl(g) proceeds through the following mechanism:

NO(g) + Cl2(g) --> NOCl2(g)
NOCl2(g) + NO(g) --> 2 NOCl(g)

1) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction?
A) Rate = k [NO] [Cl2]
B) Rate = k [NO]2 [Cl2]
C) Rate = k [NO] [Cl2]2
D) Rate = k [NO]1/2 [Cl2]
E) Rate = k [NO] [Cl2]1/2
F) Rate = k [NO]2
G) Rate = k [NO]2 [Cl2]1/2

2) What would the rate law be if the first step of this mechanism were rate-determining?

A) Rate = k [NO] [Cl2]
B) Rate = k [NO]2 [Cl2]
C) Rate = k [NO] [Cl2]2
D) Rate = k [NO]1/2 [Cl2]
E) Rate = k [NO] [Cl2]1/2
F) Rate = k [NO]2
G) Rate = k [NO]2 [Cl2]1/2
H) Rate = k [NO]

Explanation / Answer

B) Rate = k [NO]2 [Cl2] A) Rate = k [NO] [Cl2]

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