1.Calculate the number of moles of PCl5 that can be produced from 30.0 of P4 (an

Question

1.Calculate the number of moles of PCl5 that can be produced from 30.0 of P4 (and excess Cl2 ).
2.Calculate the number of moles of PCl5 that can be produced from 53.0 of Cl2 (and excess P4 ).
Then, compare the two values. The reactant that produces the smaller amount of product is the limiting reactant

Explanation / Answer

In Actual the Reaction is P4 + 10Cl2 ====> 4PCl5 Therefore Here No. of Moles of P4 present = 124 g(approx) So moles of P4 present = 30/124 = 0.24 moles Therefore Moles of PCl5 made = 4*Moles of P4 = 0.24*4 = 0.96 moles ======================================== P4 + 10Cl2 ====> 4PCl5 Here No. of Moles of Cl2 present = 53/71 = = 0.746 moles Moles of PCl5 made = (4/10)*moles of Cl2 = 0.298 moles

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