1.Calculate the net torque (magnitude and direction) on the beam in Figure P8.3
ID: 2258131 • Letter: 1
Question
1.Calculate the net torque (magnitude and direction) on the beam in Figure P8.3 about the following axes.
(a) an axis through O, perpendicular to the page
N
Explanation / Answer
1)
a) Tnet = 2*25*sin(60) -4*10*sin(20)
= 29.62 N.m
b)
Tnet = 2*30*sin(45) - 2*10*sin(20)
2)
net torque about the point O should be equal to zero.
Tnet = Ft*0.08*sin(12) - Fg*0.29 = 0
Ft = Fg*0.29/(0.08*sin(12)
= 732.28 N
net force in y-direction should be = 0
Ft*sin(12) - Fg - Fsy = 0
Fsy = Ft*sin(12) + Fg
Fsy = 194.25
netforce in x-direction should be equal to zero.
Fsx - Ft*cos(12) = 0
Fsx = Ft*sin(12) = 716.28 N
Fs = sqrt(Fsx^2+Fsy^2) = 742.15 N
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