take it aboard the Enterprise to determine some of its physical properties. You
ID: 726247 • Letter: T
Question
take it aboard the Enterprise to determine some of its physical properties. You find that it has a melting point of 1000. 0 EC and is relatively heavy, density 11. 655 g/mL and that the radius of the atom is found to be 144. 8 pm. Into what type of unit cell (i. e. , simple cubic, face-centered cubic, or body-centered cubic) does this material crystallize? Be sure to fully support your answer. The apparent atomic mass is 120. 5 amu. Remember that 1 amu = 1. 660538783 times 10!24g. Uranium-235 is an important nuclear fuel. However, the 23:>U isotope is only a very small amount of naturally occurring uranium. Therefore, taking advantage of gas diffusion rates and molar masses, naturally occurring uranium(IV) oxide is converted to uranium(IV) fluoride and this in turn is converted to uranium(VI) fluoride in a reaction with fluorine gas. The uranium(VI) fluoride is a gas and the different masses of the two uranium(VT) fluoride isotopes can be separated. Using the data below, determine the lattice energy, HLlttice Energy, of the uranium(IV) fluoride that is formed in the reactions described above. U(s) + 02(g) 6 U02(s) AH = ! 1084. 9 kJ/mol U02(s) + 4 HF(g) 6 UF4(s) + 2H20(g) AH = 1228. 5 kJ/mol 1/2 H2(g) + 1/2 F2(g) 6 HF(g) AH = ! 271. 1 kJ/mol H2(g) + 1/2 O2(g) 6 H20(g) AH = ! 241. 8 kJ/mol U(s) 6 U(g) AH = 527. 2 kJ/mol U(g) 6 U4+(g) + 4 e! IE : = 11800 kJ/mol F2(g) 6 2F(g) BE = 159 kJ/mol F(g) + e 6 F!(g) EA = ! 328 kJ/mol U4+(g) + 4F!(g)WUF4(s) LE. =?Explanation / Answer
LE = H(rxn1) + H(rxn2) + 4H(rxn3) - 2H(rxn4) - H(rxn5) - H(rxn6) - 2H(rxn7) - 4H(rxn8)
put the values,
LE = -13274.4 KJ
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