take off. Suppose the work done by such a catapult system is 5.0 x 107 J when ac
ID: 1785413 • Letter: T
Question
Explanation / Answer
3
work done by catpult system is
W=(1/2)mV2
(5*107)=(1/2)*m*702
m=20408.2 kg
4.
Given Vf=72 *1000/3600=20 m/s
since it starts from rest Vi=0
Work done is given by
W=(1/2)mVf2-(1/2)mVi2
W=(1/2)*1200*202-0
W=240,000 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.