1a)When magnesium carbonate, MgCO3, is treated with a dilute solution of nitric

Question

1a)When magnesium carbonate, MgCO3, is treated with a dilute solution of nitric acid, HNO3, the products are magnesium nitrate, Mg(NO3)2, water and carbon dioxide gas. What is the net ionic equation for this reaction?
(a) Mg2+(aq) + 2 NO3-(aq) ---> Mg(NO3)2(s)
(b) Mg2+(aq) + CO32-(aq) + 2 H+(aq) + 2 NO3-(aq) ---> Mg(NO3)2(s) + H2O(l) + CO2(g)
(c) MgCO3(s) + 2 H+(aq) ---> Mg2+(aq) + H2O(l) + CO2(g)
(d) MgCO3(aq) + 2 HNO3(aq) ---> Mg(NO3)2(aq) + H2O(l) + CO2(g)
(e) CO32-(aq) + 2 H+(aq) ---> H2O(l) + CO2(g)

1b)What is the average oxidation number (i.e. oxidation state) of oxygen in O2F2?
Important: If the oxidation number is fractional, enter your answer as a fraction

1c)Complete and balance the following chemical equation using the smallest whole number coefficients. Assume the reaction takes place in acidic aqueous solution. Use H + to balance charge, not H 3 O + .
Fill in the blanks:
NO3- + S2- --> S8 + NO2 (acidic solution)

The coefficient of NO3- is ____ . (enter a positive integer)
The coefficient of S2- is ____ . (enter a positive integer)
The coefficient of S8 is ____ . (enter a positive integer)
The coefficient of NO2 is ____ . (enter a positive integer)
H + appears on the ____________ (enter LHS for the left hand side or RHS for the right hand side); the coefficient of H + is ____ (enter a positive integer)
H 2 O appears on the ____________ (enter LHS for the left hand side or RHS for the right hand side); the coefficient of H 2 O is ____ (enter a positive integer)

1d)
What is the pressure (in mmHg) of the gas if the atmospheric pressure is Patm=775 mmHg, h1=20 mmHg, and h2=50 mmHg?
Enter your answer in mmHg, with 3 significant figures.
1e)A 13.0-L cylinder contains 29.0 g Cl2 at 67.0

Explanation / Answer

1a) (d) MgCO3(aq) + 2 HNO3(aq) ---> Mg(NO3)2(aq) + H2O(l) + CO2(g)

  

1b) Let the oxidation no. = x

Sinc F is more electro -ve

2*x-2 = 0 => x = 1

1c) NO3- + 2H+ + e-   ---------> NO2 + H2O -------- eqn 1

8S2- --------> S8 + 16 e- ----- eqn 2

Multiplying eqn 1 by 16 And adding to eqn 2 (to remove e)

16NO3- + 32H+ + 8S2- ---------> 16 NO2 + S8 +16 H2O

The coefficient of NO3- is 16 . (enter a positive integer)
The coefficient of S2- is 8 . (enter a positive integer)
The coefficient of S8 is 1 . (enter a positive integer)
The coefficient of NO2 is 16 . (enter a positive integer)
H + appears on the LHS (enter LHS for the left hand side or RHS for the right hand side); the coefficient of H + is 32 (enter a positive integer)
H 2 O appears on the RHS (enter LHS for the left hand side or RHS for the right hand side); the coefficient of H 2 O is 16 (enter a positive integer)

1d) Pressure of gas = Patm + (h2 -h1) = 805 mmHg

1e) T = 67 C = 273.15 + 67 = 340.15 K

R = 0.082 L atmK1mol1

n = 29.0/(2*35.5) = 0.408 moles

V = 13.0 L

PV = nRT

=> P = 0.408*0.082*340.15/13 = 0.875 atm

1f) For

P = 7.45 atm

V = 31.0 L

R = 0.082 L atmK1mol1

T = 24.9 + 273.15 = 298.05 K

PV = nRT

=> n = PV/RT = 7.45*31.0/(0.082*298.05) = 9.45 moles

Mass in the container = 9.45*32 = 302 gm

Mass released = 425-302 = 123 g

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