1a) The pOH of an aqueous solution at 25°C was found to be 9.70. The pH of this
ID: 522698 • Letter: 1
Question
1a) The pOH of an aqueous solution at 25°C was found to be 9.70. The pH of this solution is . The hydronium ion concentration is M. The hydroxide ion concentration is M.
1b) The pH of an aqueous solution at 25°C was found to be 3.80. The pOH of this solution is . The hydronium ion concentration is M. The hydroxide ion concentration is M.
1c) The pH of an aqueous solution at 25°C was found to be 12.00. The pOH of this solution is . The hydronium ion concentration is M. The hydroxide ion concentration is M.
Explanation / Answer
1a)
pOH = 9.70
pH = 14 - 9.70 = 4.30
pH = -log [H3O+]
4.3 = -log [H3O+]
[H3O+] = 5.012*10^-5 M
pOH = -log [OH-]
9.7 = -log [OH-]
[OH-] = 1.995*10^-10 M
1b)
pH = 3.80
pOH = 14 - pH = 14 - 3.80 = 10.20
pH = -log [H3O+]
3.8 = -log [H3O+]
[H3O+] = 1.585*10^-4 M
pOH = -log [OH-]
10.2 = -log [OH-]
[OH-] = 6.31*10^-11 M
1C)
pH = 12
pOH = 14 - pH = 14 - 12 = 2.0
pH = -log [H3O+]
12.0 = -log [H3O+]
[H3O+] = 1*10^-12 M
pOH = -log [OH-]
2.0 = -log [OH-]
[OH-] = 1*10^-2 M
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