Based on the balanced chemical reaction, determine the limiting reactant and the

Question

Based on the balanced chemical reaction, determine the limiting reactant and
theoretical yield of water (in g).
4C2H5NO2(S) + 9O2(g)?8CO2(g) +10 H2O(l) +2N2(g) :
a. Combine 45.0 g of both glycine (C2H5NO2) and oxygen

Explanation / Answer

4C2H5NO2(S) + 9O2(g)=======>8CO2(g) +10 H2O(l) +2N2(g) : Moles = mass/molar mass Moles of C2H5NO2 = 45g/75g/mol = 0.6 mol C2H5NO2 Moles of O2 = 45 g/32g/mol = 1.4 mol O2 Here the molar ratio is 4 C2H5NO2 : 9 O2 0.6C2H5NO2/4 =0.15 mol C2H5NO2 1.4 mol O2/9 = 0.16 mol O2 So C2H5NO2 is the limiting reagent. Now 0.6 mol C2H5NO2 * (10 mol H2O/4 mol C2H5NO2*(18 g H2O/1 mol H2O) 27 g H2O

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