40, Balance the following equation: B:0s(s) + HF()-BFs(g) +H:O) C) E) 41. B2O3(s

Question

40, Balance the following equation: B:0s(s) + HF()-BFs(g) +H:O) C) E) 41. B2O3(s) + 2HF(l) 2BF3(g) + H2on B2O3(s) + 6HF(1) 2BF3(g) + 6H20() Balance the following equation: CsHIsOs)+ 0:(g)->H:0(g)+CO (g) C) D) E) 2CsHisO3() + 2202(g) 9H20(g) + 1 6COdg CsHi8O3() + 1302(g) 1811:0 g) + 8CO2(g) 2Callisod) +1 702(g)18H2O(g) +16CO2(g) 42. A) 1.13 x 104 molecules B) 1.48 x 1025 molecules C) 2.44 x 1022 molecules D) 3.22 x 102 molecules E) 6.98 x 1021 molecules How many molecules are in 0.534 mol of ethanol, C2HsOH? 43The number of hydrogen atoms in 0.050 mol of C,HsO, is A) 3.0 × 10-2 H atoms B) 1.2 x 10 H atoms C) 2.4 × 1023 H atoms D) 4.8 x 10" H atoms E) None of these choices is correct.

Explanation / Answer

Ans 40 : A) B2O3 (s) + 6HF (l) = 2BF3 (g) + 3H2O (l)

To balance the chemical reaction , start by identifying the elements on the both sides of equation. Then note down the initial number of atoms present and then equate these atoms on both the sides of equation.

So the balanced reaction here is given as :

B2O3 (s) + 6HF (l) = 2BF3 (g) + 3H2O (l)

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.