ee species or tw Name Submit through Moodle CHE 222-001/002 Fall 2017 Due Septem

Question

ee species or tw Name Submit through Moodle CHE 222-001/002 Fall 2017 Due September 22, 2017 at 8 am Stoichiometry Workshop- Worksheet 1. Print and complete (Showing ALL steps) even how to calculate molar mass 2. Write and/or balance the following equations (remember the diatomic elements and to criss-cross charges for ionic compounds!!!) Use the mole ratios from the balanced equations to solve the following stoichiometry problems. Use units and labels in all conversions, and round your answer to sig figs. 3. 3 pts equation, 2 pts balanced, 8 pts for each stoichiometry!!! 4. Submit completed work in Moodle 5. Potassium chlorate decomposes into potassium chloride and oxygen gas. How many moles of oxygen are produced when 3.0 moles of potassium chlorate decompose completely? 6. 7. Butane (C4H10) undergoes combustion. Balanced Equation: CO2(g) +H:00) How many grams of CO2 are produced when 88 g of O2 are reacted with an excess of butane? 8. 9. Water decomposes into hydrogen gas and oxygen gas by electrolysis. 10. How many grams of hydrogen will be produced when 6.0 moles of oxygen are produced?

Explanation / Answer

Ans 5 :

The balanced reaction for the decomposition of potassium chlorate is given as :

2KClO3 = 2KCl + 3O2

Ans 6 :

2 moles of compound when decomposes , gives 3 moles of oxygen

So when 3 moles of chlorate decomposes , the number of moles of oxygen produced will be :

= (3 x 3) / 2

= 4.5 moles of oxygen

Ans 7 :

The balanced reaction for the combustion of butane is given as :

2C4H10 (l) + 13O2 (g) = 8CO2 (g) + 10H2O (g)

Ans 8 :

Number of moles of O2 = 88 / 31.999 = 2.75 mol

13 mol O2 give 8 mol CO2

So 2.75 mol O2 will give : ( 2.75 x 8) / 13 = 1.69 mol CO2

Mass of CO2 produced = 1.69 x 44.01

= 74.48 grams

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