imiting Reagent and Reactant and Percent Yield QUESTION ANSWER Excess reactant:

Question

imiting Reagent and Reactant and Percent Yield QUESTION ANSWER Excess reactant: H Grams remaining: 6.8 g of H Excess reactant: H The limiting reactant is the chemical substance that determines the amount of product(s) that can ultimately be formed in a reaction. During the reaction, the limiting reactant is completely consumed or used up, and therefore, causes the reaction to stop. Grams remaining 324 gof H, The limiting reactant can be identified through stoichiometric calculations. After comparing the results, the reactant that produces the smaller mass of product is identified as the limiting Excess reactant: N Grams remaining: 6.8 g of N Excess reactant: N Grams remaining: 3.24 g of N reactant. Determine the excess reactant and calculate the mass of the remaining excess reactant after 15.0 grams of N, and 10.0 grams of H, react. I DON'T KNOWYET N,(g)+3 H,(g) 2 NH,(g) For the calculations in this module, the molar mass of an element will be rounded to the hundredths place (0.01 g).

Explanation / Answer

Solution :-

Balanced reaction equation

N2 + 3 H2 ----- > 2NH3

Lets calculate the mass of H2 needed to react with 15.0 g N2

(15.0 g N2 * 1 mol / 28.01 g)*(3 mol H2 / 1 mol N2)*(2.02 g / 1 mol H2)=3.2 g H2

So 3.2 g H2 is needed for the reaction with 15.0 g N2

The mass of H2 given is more than mass of H2 needed for the reaction therefore the excess reagent is H2

Mass of excess H2 remain = [ initial mass of H2] – [mass of H2 reacted]

                                                = 10.0 g – 3.2 g

                                                = 6.8 g H2

Therefore answer is option 1

Excess reactant: H2

Grams remaining : 6.8 g

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