4. A student has prepared 0.05 M solution of CoHs-OH and has added to it 0.05 M

Question

4. A student has prepared 0.05 M solution of CoHs-OH and has added to it 0.05 M solution of di- iso-propylamine (HN(CH(CH3)2)2. (8 points) (i) Write the equation for the acid-base reaction that might occur. (ii) with curved arrows track the movements of electron pairs. d for the base, Conjugate base for the acid. (iv) Calculate the percentage of phenolate (C&HsO) taking into account that pKa of the conjugate acid of di-iso-propylamine equals 11 and pKa of phenol (C&HsOH) equals 10. O. Conjugasr C8 pra: TO base acid Ar) a (AH) C6+3 Pea(AH)".logcC+"J.LaTRO) f electrons and draw all possible resonance

Explanation / Answer

10 part of phenolate. Asume 40% of phenlate and 60% of di iso propylamine (it is conjugated acid compound )  

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.