A balloon containing 4.28 L of an unknown gas at 1.00 atm and 298 K has a mass o

Question

A balloon containing 4.28 L of an unknown gas at 1.00 atm and 298 K has a mass of 16.90 g. The empty balloon has a mass of 2.24 g.What is the molar mass of the gas in the balloon? Select one: a.400 gimo b. 32.0 gmol c. 83.8 g/mol O d. 96.6 g/mol A 20.4 L tank at 298 K contains nitrogen gas with a partial pressure of 6.8 atm and helium gas with a partial pressure of 7.2 atm. What is the total pressure in the tank if the temperature is increased to 318 K? Select one: a. 7.26 atm b. 14.9 atm o c. 7.68 atm O d. 13.1 atm

Explanation / Answer

Answer of the 1st question is c. 83.8 g/mol

Calculation:

Volume of the gas (V) = 4.28 L

Pressure of the gas (P) = 1.00 atm

Temperature (T) = 298 K

Total mass = 16.90 g

Mass of the empty baloon = 2.24 g

Mass of the gas (m) = (16.90 - 2.24) g = 14.66 g

From the ideal gas equation

PV = nRT

where n = mole of the gas = m/M, M = molar mass

R = Universal gas constant = 0.08206 L·atm/(mol·K)

PV = mRT/M

1.00 x 4.28 = (14.66 g x 0.08206 x 298)/M

or, M = (14.66 g x 0.08206 x 298)/4.28

or, M = 358.5/4.28

or, M = 83.8 g/mol

Therefore the molar mass of the gas = 83.8 g/mol

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