It’s been so long since I’ve done a question like this, I don’t even know where
ID: 713937 • Letter: I
Question
It’s been so long since I’ve done a question like this, I don’t even know where to start! Anything would help
Sum A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of and carbon tetrachloride. The chemist plans to try to identify the unknown liquid by measuring the Data Sheets (MSDS), the chemist finds the following information: liquid density 0.89 3 0.79 pentane 0.638 dimethyl sulfoxide carbon tetrachloride 1.6 Next, the chemist measures the volume of the unknown liquid as 0.943 L and the mass of the unknown liquid as 881.g. Calculate the density of the liquid. Be sure your 10 g / om Explanation 0%
Explanation / Answer
Let start with volume of unknow liquid
0.943 litre equals to 943 cm3
the density of a liquid calculated as = mass of liquid divided by volume of liquid
Hence, in this case density = 881/943 (g/cm3)
which is equals to = 0.934 g/cm3 or 9.3 x 101 g/cm3
This is the answer to the fist question.
the answer to the second question is : yes
it is possible to identify the unknow liquid as its calculated density value is very near to density of dimethyl sulfoxide. considering 0.943 almost equal to 1.
hence answer to third question is: dimethyl sulfoxide
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