Question 1) The radius of a uranium atom is 149 pm. How many uranium atoms would
ID: 713852 • Letter: Q
Question
Question 1) The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 4.38 mm?
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Question 2) The mass of a single tungsten atom is 3.05×10-22 grams. How many tungsten atoms would there be in 258 milligrams of tungsten?
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Please write out all the steps clearly as possible, thanks!
Explanation / Answer
1)
diameter of uranium atom = 149*2 pm
= 298 pm
= 298*10^-12 m
= 2.98*10^-10 m
total distance = 4.38 mm
= 4.38*10^-3 m
Use:
Number of uranium atoms = total distance / diameter of uranium atom
= (4.38*10^-3 m) / (2.98*10^-10 m)
= 1.47*10^7
Answer: 1.47*10^7
2)
mass of 1 atom = 3.05*10^-22 g
total mass = 258 mg
= 258*10^-3 g
= 0.258 g
Use:
Number of atoms = total mass / mass of 1 atom
= 0.258 g / (3.05*10^-22 g)
= 8.46*10^20
Answer: 8.46*10^20
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