How many grams of iodine are produced from 7.00 moles of chlorine according to t
ID: 713721 • Letter: H
Question
How many grams of iodine are produced from 7.00 moles of chlorine according to the following reaction? 3C12(g) + 2 Fel2(g)- 2 Fecl3(g) + 2 12(g) 1180 grams iodine 2665 grams iodine 592.6 grams iodine e 183.9 grams iodine D Question 8 1 pts Which of the following equations accurately represents the calculation needed to determine the number of grams of FeCl3 produced from 4.00 moles of Cl2? 3 CI2(g) + 2 Fel2(g)-, 2 FeClg(g) + 2 12(g) - 00376 mol FeCl 2 mol FeCl3 162.15 g FeCh Ch x 2 mol 3 mol FeClh 162.15&Feclh; 4 mol @ “0016 g Fech x ec 162. i 5 g Fec,Explanation / Answer
7. 3 moles of Cl2 gives you the 2 moles of I2
7 moles of Cl2 gives 14/3 moles of the Iodine.
Mass of iodine =14x253.8/3= 1184.4 g = 1180 g
Option A
8. Option C
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.