Please help quick. Interpreting NMR spectra of an adduct. THNMR pectrurnofPPh\"B

Question

Please help quick. Interpreting NMR spectra of an adduct.

THNMR pectrurnofPPh"BH3(0.6-2.0pprmregion. Thepeakat 1.57 ppm i narrow peaks at 1.2-1.3 ppm are impurities. 0.85 1.13 1.77 1.49 st 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 H NMR ppm from Si(CH,) {"B} NMR spectrum ofPPhyBH3 (0.6-4.0 ppm region). The peak at 1.57 ppm s water. 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 Hp B) NMR ppm from Si(CHj) The four broad peaks in the H NMR spectrum collapse to a doublet in the 'HfBNMR spectrum. What is happening here? What information can be obtained from the doublet centeredat1.3ppmintheTTB NMR spectrum? 50

Explanation / Answer

Decoupling experiments are run in order simply the NMR spectra. The same technique is applied in this case also. In the first case B11 is decoupled resulting in the conversion of the big signal into a doublet.

Doublet gives information abotut the P31 and 1H coupling. Two bond coupling constant of P31 with 1H can be obtained.

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.