If 26.23mL of potassium permanganate solution is required to titrate 1.041g of f

Question

If 26.23mL of potassium permanganate solution is required to titrate 1.041g of ferrous ammonium sulfate hexahydrate, FeSO4(NH4)SO46H2O.. Calculate the molarity of KMnO4 solution

Explanation / Answer

the equation for the titration is 5Fe+2 + MnO4- + 8H+ --> 5Fe+3 + Mn+2 + 4H20 Molar mass of FeSO4(NH4)2SO4*6H2O is 392.1406 g/mol moles of FeSO4(NH4)2SO4 6H2O = 1.041/392.14 = 0.002654 moles of Fe = 0.002654 from the equation , moles of MnO4- = 0.002654 / 5 = 0.0005308 these are in 26.23 mL so moles per liter = 0.0005308 * 1000 / 26.23 = 0.0202 moles per liter KMnO4 molarity=(0.0202/0.02623)=0.77M

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