Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublim
ID: 708713 • Letter: D
Question
Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublimes according to the following equation:
CO2 (s) = CO2 (g)
<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /> <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />. When dry ice is added to warm water, heat from the water causes the dry ice to sublime more quickly. The evaporating carbon dioxide produces a dense fog often used to create special effects. In a simple dry ice fog machine, dry ice is added to warm water in a Styrofoam cooler. The dry ice produces fog until it evaporates away, or until the water gets too cold to sublime the dry ice quickly enough. Suppose that a small Styrofoam cooler holds 15.0 liters of water heated to 86 degre celcius .
a)Use standard enthalpies of formation to calculate the change in enthalpy for dry ice sublimation. (The delta Hf for CO2 is - 427.4 kJ/mol ).
delta H rxn =
b)Calculate the mass of dry ice that should be added to the water so that the dry ice completely sublimes away when the water reaches 24degre celcius . Assume no heat loss to the surroundings.
m dry ice =
Explanation / Answer
15 liters H2O = 15*1000g = 15,000 grams
heat needed to raise one gram water, one degree celsius = 4.18J
4.18J * 15,000g = 62,700J = 62.7kJ needed per degree C
85 - 16 = 69C temp drop needed
62.7 kJ * 69C = 4326.3kJ needed from CO2
enthalpy of CO2 = 393.51kJ/mol
CO2 = 44g/mol = 22.73 moles/kg
393.51kJ/mol * 22.73 moles/kg
= 8,943.4 kJ/kg
4326.3kJ / 8,943.4 kJ/kg = .484 kg of CO2 needed
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