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Becomes like this when you put it in math terms (like how did they decide which

ID: 705704 • Letter: B

Question


Becomes like this when you put it in math terms (like how did they decide which to put on the top and bottom??) QUESTION t takes 2.55 J of heat to raise the temperature of Object A by 1 °C, and 4.78 J to raise the temperature of Object B by 1 C. Suppose A and B are brought into contact. A is initially hotter. A is seen to cool down by 14.5 ?. How would you calculate the rise in temperature of B? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. EXPLANATION

Explanation / Answer

heat capacity is is the amount of heat required to rise the temperature of an object by 1 deg.c. So given data is related to heat capacity. When one body gains heat which is reflected in the form of temperature , the other body looses heat

heat gained = heat lost. A is loosing heat and B is gaining heat

heat capacity of A* temperature drop = heat capacity of B* temperature rise,

2.55 J/deg.c*14.5 deg.c= 4.78 J/deg.c* temperature rise

temperature rise= 2.55*14.5/4.78=7.73 deg.c, rise in temperature

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