2) Calculate the AGo rxn using the following information. 2 HNO3(aq)+ NO(g)-3 NO
ID: 704606 • Letter: 2
Question
2) Calculate the AGo rxn using the following information. 2 HNO3(aq)+ NO(g)-3 NO2(g) H200) AH°f (kJ/mol)-207.0 91.3 33.2 -285.8 S° (J/mol K) 146.0 210.8 240 70.0 a. Calculate the ?Gon under the following conditions: i) under standard conditions ii) with T-250 °C and all partial pressures at 1 atm and [HNO3]1.0 M i) with T-25 °C, PNo 3.0 atm, PNo2 0.50 atm, and [HNOs 0.25 M b. Calculate the equilibrium constant for this reaction under standard temperature conditions c. Calculate the equilibrium constant for this reaction at 250 °CExplanation / Answer
ii) DeltaG = DeltaG0 + RT ln Q
Q = p3[NO2] / [HNO3]2 pNO
Q = 1 / 1 X 1 = 1
lnQ = 0
DeltaG = DeltaG0 = 50.825 kJ
iii) DeltaG = DeltaG0 + RT ln Q
Q = p3[NO2] / [HNO3]2 pNO = (0.5)3 / (0.25)2 X 3 =0.667
lnQ = -0.405
R = 8.314 X 10-3 kJ / mol K
T = 298 K
DeltaG = 50.825 + 8.314 X X 10-3 X 298 X (-0.405) = 49.82 kJ
b) equilibrium constant under standard conditions will be
DeltaG0 = -RT lnKeq
50.825 = - 8.314 X 10-3 X 298 X ln Keq
Keq = 1.232 X 10-9
c) at 250 0C
DeltaG0 = -RT lnKeq
49.82 = - 8.314 X 10-3 X 523 X ln Keq
Keq = 1.065 X 10-5
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