9:27 LTE XExtra Credit Assignment.pdf 1 of 2 Extra Credit Assignment Instruction
ID: 702683 • Letter: 9
Question
9:27 LTE XExtra Credit Assignment.pdf 1 of 2 Extra Credit Assignment Instructions: type up your answers, show al work with units, equations must be typed in the proper formot An isolated system, consists of 164 kg of water at 30 C and an ice oube measuring 8.434 cm on each side at-20"C They are alowed to cont to thermal 1.Show the solved mathematical formula for Te in terms of the variables below Mass of water Mass of ice Initial temperature of ice Heat of fusion for water, 333 551g Specific heat capacity of water, 4184? of ice 2.11Jdk Hints: 2. Using the equation you derived earlier, determine the value of Tin C, report the value to three significant figures. Hint: the density of ice is 0.9167 g/em 3. Assuming the water at thermal equilibrium is allowed to equillbrate with earth's atmosphere (78.09% NL 20.95% 0, 0,93% Ar etc.L calculate the concentration of dissolved oxygen in ppm using the Henry's law data below. (mol kg atm 2.7058 2.6551 2.6014 20 21 23 25 2.5060 24582 26 27 28 4135 2.3717 2.3300 3 Open With PrintExplanation / Answer
1.
Let us consider that the ice cubes are added to water in an insulated vessel.
As we know that qsystem + qsurroundings = 0
Since the system is isolated, the surroundings are restricted to the water in the vessel:
qsystem = -qsurroundings
Heat lost by water = Heat gained by ice
Heat lost by water = mwater * Cwater * (Teq- Twater)
Heat gained by ice = mice * Cice * (Teq - Tice) + (mice * Hf)
On equating the above two,
- mwater * Cwater * (Teq- Twater) = mice * Cice * (Teq - Tice) + (mice * Hf)
-mwaterCwaterTeq + mwaterCwaterTwater = miceCiceTeq - miceCiceTice + miceHf
mwaterCwaterTwater + miceCiceTice - miceHf = miceCiceTeq + mwaterCwaterTeq
Teq = (mwaterCwaterTwater + miceCiceTice - miceHf)/(miceCice+ mwaterCwater)
2.
Given: 16.4 kg water at 30 deg C
Ice cube of side 8.434 cm at -20 deg C
Volume of cube = (side)3
= 599.930 cm3
Mass of ice = density * volume
= 0.9167 * 599.930
= 549.956 g
Putting all the values in the above equation:
Teq = 299.689
Teq = 26.539 deg C
[Be very careful about the units while putting the values in the equation]
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